cost????

[RS4rally1124]

whats the cost of this thing to run a car in???

JT

[Chris LaPanse]

If you're worried about that, you shouldn't be entering (lol) :D

[microrcdude]

no we just wanna know, cause we have some ideas

[Mr. Constructor]

As it is free celebration of speed (the classes are for all kinda people) the prices will vary, as normal sedans with 20 V lipo Systems and a powerful BL system will run easily within 80 it´ll be cheap (around 800 USD i think) but this might be very hard to control AND there willbe better ones, the price is open to the end i think, several ones are trying to use a jet engine, thus alone costs around 2000 USD and more !!

so there will be a chance for everybody, damn bad that i do not have the time and money and take aplane to you and watch the event, from europe it´ll be alittly costly . . . . ;-)

Good Luck to all the contestants !!

[RS4rally1124]

oh thnx man i know the costs of my car. i mean is there an entry fee per car or anything??


JT

[Mr. Constructor]

For totally free (meaning almost no sponsors ) definately yes, the others ???

Hmmm, i dunno really !!

How many days will that be going, the full contestants are propably a few more than it could be done in 1 day !!

[Potato]

Cost...

Lets say you go ALL OUT and spend $2000 on a 20 inch long car.

Now, since the rules say 40 inches is the limit, another guy, who wants more speed, goes all out. Lets see how much he'd have to spend:

Since a 40" car is obviously twice as long as a 20" car, that would be 2^3 increase in volume, or 8 TIMES the volume. So JUST to be proportional in cost, the 40" car would cost 2000*8 = $16,000.

You'd have to be outright wasteful and unjudicious to spend $16,000 on a 20" car (I can't even see how you could do that), but with a 40" car, $16,000 is not even enough to go ALL OUT.

If you want a chance at winning, you can't just rely on a good design and clever engineering. That won't cut it. You need lots of money, since they increased the length limit to 40". The ultimate 40" car will DESTROY the ultimate 20" car.

[RS4rally1124]

ok i dotn care about car cost i know my car will cost a lot i want to know if there is an entry fee to this thing per car entered. thats ENTRY FEE. i have a cool car that is probably unlike the rest that will be there but since a friend is entering and driving my car i need to know how much to send him and everything.

JT

[rpmmaxxed]

Lets say you go ALL OUT and spend $2000 on a 20 inch long car.

Now, since the rules say 40 inches is the limit, another guy, who wants more speed, goes all out. Lets see how much he'd have to spend:

Since a 40" car is obviously twice as long as a 20" car, that would be 2^3 increase in volume, or 8 TIMES the volume. So JUST to be proportional in cost, the 40" car would cost 2000*8 = $16,000.

You'd have to be outright wasteful and unjudicious to spend $16,000 on a 20" car (I can't even see how you could do that), but with a 40" car, $16,000 is not even enough to go ALL OUT.

If you want a chance at winning, you can't just rely on a good design and clever engineering. That won't cut it. You need lots of money, since they increased the length limit to 40". The ultimate 40" car will DESTROY the ultimate 20" car.





That is the stupidist statement I have ever heard...

[Potato]

That is the stupidist statement I
have ever heard...

And that is the most blanket, unqualified, unsupported
response I have ever heard, not to mention rude and
disrespectful.

What part of it do you not understand?

Was it the calculation? For a 16 year old, you should
be able to understand basic mathematics involving
length, area, and volume. I doubt this is any problem
for you. I made no mistake in my calculation. The
numbers are there to prove a point.

Is it that you don't believe it's possible to spend
$16000 on a 40" car? If that's the case, you don't
have to take my word for it:


• Now until Sept 30 - Beg wife to let me do this,
(which will probably end up costing me a real car),and research engine components and
specifications.
http://www.radiocontrolzone.com/forums/showthread.php?p=1525969#post1525969

So that's one person who has stated such. I'm sure
there are others who don't post here but plan to do the same.

Is it because of the physics involved? I'll assume you
understand that while power is roughly proportional to
volume (L^3), drag is proportional to frontal area
(L^2). The implications of this should be obvious.

So where exactly did I make a grievously "stupid"
statement?

[rpmmaxxed]

Simply doubling the cars length will not cause a "total cost" tally to be equal to that of the volume increase "for this arguments case, $2,000 for 20" car, and $16,000 for a 40" car". Components that are found on the 20" car can and will be the same as on the 40" car. Such as cells, receiver, servo, wheels, suspension, etc.

Blatently saying that a car of 40" in length will be 8X the cost of the 20" car due to the volume difference in not in any way an accurate statement.

[RS4rally1124]

ok someone lock this plz

JT

[Potato]

Simply doubling the cars length will
not cause a "total cost" tally to be equal to that of
the volume increase "for this arguments case, $2,000
for 20" car, and $16,000 for a 40" car". Components
that are found on the 20" car can and will be the same
as on the 40" car. Such as cells, receiver, servo,
wheels, suspension, etc.

Blatently saying that a car of 40" in length will be
8X the cost of the 20" car due to the volume
difference in not in any way an accurate
statement.

You are completely missing the point. My analogy
referenced the material cost as a rough calculation.
If you take a block of material, double one linear
dimension and keep the proportions the same, the cost
of that block of material will increase 8-fold. If you
merely scale an existing 20" car into a 40" car and
maintain ALL proportions, the material cost alone will
be roughly 8 times.

The numbers also serve as an illustration of the
increase in cost not only from materials, but from the
increase in complexity of design and fabrication. A
well
designed 40" car will NOT simply look like a scaled-up
20" car. You can't think of things so simply. Does a
full-scale car look like a big version of a 1/12 scale
pan car? If you double the size, roughly speaking,
there is a increase in complexity/cost to the power of
3. The parts count increases, the parts complexity
increases, and the design work increases. For example,
the machinery necessary to machine the
more intricate parts for a 40" car are larger, more
expensive and more complex than those necessary for a
20" car, subsequently there is a corresponding price
increase
for fabrication.

Components such as "cells, ... servo, wheels,
suspension, etc" will NOT be the same.
You are assuming that a 40" car will run on a tiny
servo, a 6-cell sub-c battery pack, a 540 motor, and a
1/10
scale suspension with 1/10 scale tires. In reality,
the only thing that can actually stay the same is the
receiver/radio.

To give a very crude real-life example, a FG
Modellsport 1/5
scale comp chassis costs about 2100 USD*. As the 1/5
scale is roughly double the length of a 1/10, you can
divide its price by 8 as I've shown already. 2100/8 =
262.5, which is roughly the price of a high end 1/10
scale touring chassis.

In this contest, we will (supposedly) see the "best in
the world," thus I expect true engineering principles
applied to very well thought out, optimized designs.
For a truly "world-class," well engineered 40" custom
chassis, $16,000 is not an outrageous cost. Of course,
it's quite possible we won't see any world-class
competition or world-class engineers participating,
and consequently we won't see anything that is
anywhere near the "Formula 1" of R/C car design. If
that's the case though, why call it "World's Fastest?"

Maybe I am just expecting too much from this contest.


*
found at:
http://www.centrehobbies.co.uk/acatalog/cars_fg_modellsport.html

[microrcdude]

S O M E O N E P L Z L O C K T H I S T H R E A D!!!!!!!!!!!!!!!!!!